You are given three non-negative integers (x), (y) and (z). Determine whether there exist three non-negative integers (a), (b) and (c) satisfying the following three conditions: (a \mathbin{\&} b = x) (b \mathbin{\&} c = y) (a \mathbin{\&} c = z) where (\mathbin{\&}) denotes the bitwise AND operation . Each test contains multiple test cases. The first line contains the number of test cases (t) ((1 \le t \le 10^4)). The description of the test cases follows. The first and only line of each test case contains three integers (x), (y) and (z) ((0\le x, y, z\le 10^9)) — the target values of (a \mathbin{\&} b), (b \mathbin{\&} c) and (a \mathbin{\&} c), respectively. For each test case, output " YES " if there exists three non-negative integers (a), (b), and (c) satisfying the above conditions, and " NO " otherwise. You can output the answer in any case (upper or lower). For example, the strings " yEs ", " yes ", " Yes ", and " YES " will be recognized as positive responses. In the first test case, (a = 3), (b = 5), and (c = 9) satisfies the condition as (3 \mathbin{\&} 5 = 1), (5 \mathbin{\&} 9 = 1), and (3 \mathbin{\&} 9 = 1). In the second test case, (a = 7), (b = 3), and (c = 22) satisfies the condition as (7 \mathbin{\&} 3 = 3), (3 \mathbin{\&} 22 = 2), and (7 \mathbin{\&} 22 = 6). In the third test case, it can be proven that there are no three non-negative integers (a), (b), and (c) such that (a \mathbin{\&} b = 4), (b \mathbin{\&} c = 8), and (a \mathbin{\&} c = 12).