B'Let 's define logical OR as an operation on two logical values (i. e. values that belong to the set {0, xe2 x80 x891}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical OR of three or more logical values in the same manner: where is equal to 1 if some ai xe2 x80 x89= xe2 x80 x891, otherwise it is equal to 0. Nam has a matrix A consisting of m rows and n columns. The rows are numbered from 1 to m, columns are numbered from 1 to n. Element at row i (1 xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89i xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89m) and column j (1 xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89j xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89n) is denoted as Aij. All elements of A are either 0 or 1. From matrix A, Nam creates another matrix B of the same size using formula: . (Bij is OR of all elements in row i and column j of matrix A) Nam gives you matrix B and challenges you to guess matrix A. Although Nam is smart, he could probably make a mistake while calculating matrix B, since size of A can be large. The first line contains two integer m and n (1 xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89m, xe2 x80 x89n xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89100), number of rows and number of columns of matrices respectively. The next m lines each contain n integers separated by spaces describing rows of matrix B (each element of B is either 0 or 1). In the first line, print "NO" if Nam has made a mistake when calculating B, otherwise print "YES". If the first line is "YES", then also print m rows consisting of n integers representing matrix A that can produce given matrix B. If there are several solutions print any one.'...