B"There are less than 60 years left till the 900-th birthday anniversary of a famous Italian mathematician Leonardo Fibonacci. Of course, such important anniversary needs much preparations. Dima is sure that it'll be great to learn to solve the following problem by the Big Day: You're given a set A, consisting of numbers l, l xe2 x80 x89+ xe2 x80 x891, l xe2 x80 x89+ xe2 x80 x892, ..., r; let's consider all its k-element subsets; for each such subset let's find the largest common divisor of Fibonacci numbers with indexes, determined by the subset elements. Among all found common divisors, Dima is interested in the largest one. Dima asked to remind you that Fibonacci numbers are elements of a numeric sequence, where F1 xe2 x80 x89= xe2 x80 x891, F2 xe2 x80 x89= xe2 x80 x891, Fn xe2 x80 x89= xe2 x80 x89Fn xe2 x80 x89- xe2 x80 x891 xe2 x80 x89+ xe2 x80 x89Fn xe2 x80 x89- xe2 x80 x892 for n xe2 x80 x89 xe2 x89 xa5 xe2 x80 x893. Dima has more than half a century ahead to solve the given task, but you only have two hours. Count the residue from dividing the sought largest common divisor by m. The first line contains four space-separated integers m, l, r and k (1 xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89m xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89109; 1 xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89l xe2 x80 x89< xe2 x80 x89r xe2 x80 x89 xe2 x89 xa4 xe2 x80 x891012; 2 xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89k xe2 x80 x89 xe2 x89 xa4 xe2 x80 x89r xe2 x80 x89- xe2 x80 x89l xe2 x80 x89+ xe2 x80 x891). Please, do not use the %lld specifier to read or write 64-bit integers in xd0 xa1++. It is preferred to use cin, cout streams or the %I64d specifier. Print a single integer -- the residue from dividing the sought greatest common divisor by m."...