B'"How am I to tell which is the One?!" the mage howled. "Throw them one by one into the Cracks of Doom and watch when Mordor falls!" Somewhere in a parallel Middle-earth, when Saruman caught Frodo, he only found n rings. And the i -th ring was either gold or silver. For convenience Saruman wrote down a binary string s of n characters, where the i -th character was 0 if the i -th ring was gold, and 1 if it was silver. Saruman has a magic function f , which takes a binary string and returns a number obtained by converting the string into a binary number and then converting the binary number into a decimal number. For example, f(001010) = 10, f(111) = 7, f(11011101) = 221 . Saruman, however, thinks that the order of the rings plays some important role. He wants to find 2 pairs of integers (l_1, r_1), (l_2, r_2) , such that: Here substring s[l:r] denotes s_ls_{l+1} ldots s_{r-1}s_r , and lfloor x rfloor denotes rounding the number down to the nearest integer. Help Saruman solve this problem! It is guaranteed that under the constraints of the problem at least one solution exists. Each test contains multiple test cases. The first line contains one positive integer t ( 1 <= t <= 10^3 ), denoting the number of test cases. Description of the test cases follows. The first line of each test case contains one positive integer n ( 2 <= n <= 2 cdot 10^4 ) -- length of the string. The second line of each test case contains a non-empty binary string of length n . It is guaranteed that the sum of n over all test cases does not exceed 10^5 . For every test case print four integers l_1 , r_1 , l_2 , r_2 , which denote the beginning of the first substring, the end of the first substring, the beginning of the second substring, and the end of the second substring, respectively. If there are multiple solutions, print any. In the first testcase $'...