Codeforces Round 702 (Div. 3)

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1490 Codeforces Round 702 (Div. 3) FINISHED False 7200 118337099 Feb. 16, 2021, 2:35 p.m.

Problems

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( 33657 ) C Sum of Cubes PROGRAMMING binary search brute force brute force math

B'You are given a positive integer x . Check whether the number x is representable as the sum of the cubes of two positive integers. Formally, you need to check if there are two integers a and b ( 1 <= a, b ) such that a^3+b^3=x . For example, if x = 35 , then the numbers a=2 and b=3 are suitable ( 2^3+3^3=8+27=35 ). If x=4 , then no pair of numbers a and b is suitable. The first line contains one integer t ( 1 <= t <= 100 ) -- the number of test cases. Then t test cases follow. Each test case contains one integer x ( 1 <= x <= 10^{12} ). Please note, that the input for some test cases won 't fit into 32 -bit integer type, so you should use at least 64 -bit integer type in your programming language. For each test case, output on a separate line: You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive). The number 1 is not representable as the sum of two cubes. The number 2 is represented as 1^3+1^3 . The number 4 is not representable as the sum of two cubes. The number 34 is not representable as the sum of two cubes. The number 35 is represented as 2^3+3^3 . The number 16 is represented as 2^3+2^3 . The number 703657519796 is represented as 5779^3+7993^3 . '...

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Codeforces Round #702 (Div. 3) Editorial

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107623491 Gassa C Feb. 16, 2021, 5:07 p.m. OK D TESTS 37 77 4198400

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