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B'Implement a quantum oracle on N qubits which implements a function f(x) xe2 x80 x89= xe2 x80 x89xk, i.e. the value of the function is the value of the k-th qubit. For an explanation on how the quantum oracles work, see the tutorial blog post. You have to implement an operation which takes the following inputs: The operation doesn 't have an output; the "output" of your solution is the state in which it left the qubits. Your code should have the following signature: '... |
Tutorials
Submissions
Submission Id |
Author(s) |
Index |
Submitted |
Verdict |
Language |
Test Set |
Tests Passed |
Time taken (ms) |
Memory Consumed (bytes) |
Tags |
Rating |
39873018 |
Gassa |
G |
July 2, 2018, 3:50 p.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39872556 |
LukeKS |
G |
July 2, 2018, 3:28 p.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39869632 |
mareksom |
G |
July 2, 2018, 1:28 p.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39865779 |
john_mih |
G |
July 2, 2018, 11:05 a.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39861492 |
sharph |
G |
July 2, 2018, 8:15 a.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39856451 |
carrino |
G |
July 2, 2018, 4:06 a.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39854485 |
squirtgun |
G |
July 2, 2018, 1:50 a.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39851853 |
davidv1992 |
G |
July 1, 2018, 9:44 p.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39849114 |
burek967 |
G |
July 1, 2018, 7:08 p.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
39821520 |
gkevinyen5418 |
G |
July 1, 2018, 12:45 p.m. |
OK |
Q# |
TESTS |
6 |
249 |
0 |
|
2500 |
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